Y=4.9x^2-18x-32

Solution for Y=4.9x^2-18x-32 equation:

=4.9Y^2-18Y-32

We move all terms to the left:

-(4.9Y^2-18Y-32)=0

We get rid of parentheses

-4.9Y^2+18Y+32=0

a = -4.9; b = 18; c = +32;
Δ = b2-4ac
Δ = 182-4·(-4.9)·32
Δ = 951.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-\sqrt{951.2}}{2*-4.9}=\frac{-18-\sqrt{951.2}}{-9.8}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+\sqrt{951.2}}{2*-4.9}=\frac{-18+\sqrt{951.2}}{-9.8}
$